X^2-2x+x-2=180

Solution for X^2-2x+x-2=180 equation:

X^2-2X+X-2=180

We move all terms to the left:

X^2-2X+X-2-(180)=0

We add all the numbers together, and all the variables

X^2-1X-182=0

a = 1; b = -1; c = -182;
Δ = b2-4ac
Δ = -12-4·1·(-182)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-27}{2*1}=\frac{-26}{2}
=-13
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+27}{2*1}=\frac{28}{2}
=14
$